In the original problem, the heights are strictly increasing, as a result, there can be at most one equal pair, leading to a simple solution.

However, what if the heights are non-decreasing, instead of strictly increasing? In this case, there can be more than one equal pair in the final heights. For example, $$$[1,1,2,2,3,3]$$$ will remain the same, in which there are three equal pairs. The fact that there can be more than one equal pairs makes it impossible for us to solve the problem based on the sum and length of the original heights. For example, $$$[4,4,5,5]$$$ and $$$[3,4,5,6]$$$ are all valid heights.

How can we solve this modification?

In the Official Tutorial, it has been proved that the sequence of operations does not matter. So we can assume that when we process the $$$k$$$-th element, the first $$$k-1$$$ elements are already a valid sequence (but might not be in their final form).

Let's consider the difference of a valid sequence. It can only have $$$0$$$ and $$$1$$$. For example, $$$[2,3,3,4]$$$ has difference $$$[1,0,1]$$$. How will the difference change when future slides happen?

We can do some experiments. Supposing there is an infinite hill at the end, we will have:

$$$[2,3,3,4]$$$ ==> $$$[2,3,4,4]$$$ ==> $$$[2,3,4,5]$$$ ==> $$$[3,3,4,5]$$$

And the difference array changes like this:

$$$[,1,0,1]$$$ ==> $$$[,1,1,0]$$$ ==> $$$[,1,1,1]$$$ ==> $$$[,0,1,1]$$$

We can see that the position of $$$0$$$ in the difference array keeps moving backward until it vanishes at the end. Then it will occur again at the front.

In the following, we will call a $$$0$$$ in the difference array a "slot". In the above example, there is only one slot, what about multiple slots?

Let's see another example.

$$$[2,2,3,3,4]$$$ ==> $$$[2,2,3,4,4]$$$ ==> $$$[2,2,3,4,5]$$$ ==> $$$[2,3,3,4,5]$$$ ==> $$$[2,3,4,4,5]$$$ ==> $$$[2,3,4,5,5]$$$ ==> $$$[2,3,4,5,6]$$$

Where the difference array goes like:

$$$[,0,1,0,1]$$$ ==> $$$[,0,1,1,0]$$$ ==> $$$[,0,1,1,1]$$$ ==> $$$[,1,0,1,1]$$$ ==> $$$[,1,1,0,1]$$$ ==> $$$[,1,1,1,0]$$$ ==> $$$[,1,1,1,1]$$$