Codeforces Round #191 simpler solution to hungry sequence

Revision en1, by rohit_flawless, 2019-12-26 19:30:20

Here's simpler solution to codeforces round 191(div 2) ,question hungry sequence- https://codeforces.me/contest/327/problem/B Suppose we are given the number N. We can observe that for any N ,number divisible by N is always greater than or equal to 2*N, so we select numbers N+0,N+1,N+2,.......N+N-1 .So, Here we N satisfying conditions of hungry sequence.

Tags round #191, hungry sequence, simpler

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  Rev. Lang. By When Δ Comment
en2 English rohit_flawless 2019-12-26 19:32:58 73 Tiny change: 'Here's sim' -> 'simpler solution to hungry sequence\nHere's sim'
en1 English rohit_flawless 2019-12-26 19:30:20 416 Initial revision (published)