I was wondering a problem: Is it possible to construct a n*n matrix (call it A) such that each number from 0 to n-1 appears exactly n times and the result of A*A is a zero matrix. I know it is obvious for odd n but how about even n?
An interesting matrix problem
I was wondering a problem: Is it possible to construct a n*n matrix (call it A) such that each number from 0 to n-1 appears exactly n times and the result of A*A is a zero matrix. I know it is obvious for odd n but how about even n?
| Rev. | Язык | Кто | Когда | Δ | Комментарий | |
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| en10 |
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anothermousey | 2023-01-24 18:10:52 | 8 | ||
| en9 |
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anothermousey | 2023-01-24 18:10:13 | 0 | (published) | |
| en8 |
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anothermousey | 2023-01-24 18:09:59 | 2 | (saved to drafts) | |
| en7 |
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anothermousey | 2023-01-24 16:50:28 | 0 | (published) | |
| en6 |
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anothermousey | 2023-01-24 16:50:09 | 2 | ||
| en5 |
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anothermousey | 2023-01-24 14:42:32 | 1555 | (saved to drafts) | |
| en4 |
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anothermousey | 2023-01-12 12:14:08 | 24 | Tiny change: 'lt of A*A is a zero' -> 'lt of A*A (matrix multiplication) is a zero' | |
| en3 |
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anothermousey | 2023-01-12 12:09:40 | 4 | Tiny change: 'mber from 0 to n-1 appears e' -> 'mber from 1 to n appears e' | |
| en2 |
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anothermousey | 2023-01-12 12:00:32 | 44 | ||
| en1 |
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anothermousey | 2023-01-12 11:24:31 | 261 | Initial revision (published) |
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