First, you have to check if n is in one of the following 3 ranges: $$$48 \le n \le 57$$$, $$$65 \le n \le 90$$$, $$$97 \le n \le 122$$$.

If no, then output "Lmao".

Else, use char() to output the character associated with the number n.

#include <bits/stdc++.h>
using namespace std;
void solve()
{
   int n; cin >> n;
   if(n<48 || (n>57 && n<65) || (n>90 && n<97) || n>122) cout << "Lmao" << endl;
   else cout << char(n) << endl;
}
int main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    solve();
}