easy ragebait

For C I think you it doesn't matter which odd number it is, except for the maximum. If at least one odd exists, you could first print the maximum odd number and then m more numbers where the ith number will be maxOdd+ith even number (in descending order) and then for the remaining numbers: m+2 to n, for jth number if (j-m) is odd print the (sum of all even+maxOdd) else print 0, and add check that if there are even number of odd numbers then nth number will be 0 regardless of the parity of j-m.