| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | jiangly | 3670 |
| 3 | Kevin114514 | 3657 |
| 4 | maroonrk | 3355 |
| 5 | Um_nik | 3353 |
| 6 | squareOf105 | 3346 |
| 7 | tourist | 3343 |
| 8 | strapple | 3324 |
| 9 | heuristica | 3322 |
| 10 | jiangbowen | 3291 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | AmShZ | 143 |
| 5 | Um_nik | 141 |
| 6 | Errichto | 139 |
| 7 | adamant | 137 |
| 8 | BledDest | 133 |
| 8 | maroonrk | 133 |
| 10 | qwexd | 130 |
You start with an array containing all zeroes. You will be given some updates. Updates are in the form $$$L, R, A, B$$$. For each update, you have to add $$$A+(i-L)*B$$$ for each $$$L \leq i \leq R$$$. You will have to answer queries in the form $$$L, R$$$. For each query, you have answer what's the maximum element in $$$[L, R]$$$ range.
The range sum query version of this problem can be solved with segment tree with lazy propagation. However, I can't think of a way to solve this one.
Hello there!
There will be a contest for the freshmen of CSE department, BUET. We will be hosting a replay of the contest on CodeChef on 9 PM BST (3 PM UTC). It is an open contest. Anyone can participate in the contest. The contest duration is 3 hours. Here's the contest link: https://www.codechef.com/BCRR2018
The problems would be rather observation and implementation based than algorithmic nature. So, you don't need to know complex classical algorithms to do better in the contest!
Problemsetters: solaimanope, Anachor, SlowDecay, Fullmetal_Algorithmist, _Plague_, _comfortably_numb, rebornplusplus, _LzY_, rogue_33
Update: Editorial
| Название |
|---|


