You can find the solution here

1. Create a new directed graph having 2*n nodes.
2. The first n nodes are marked as H1, H2, ...., Hn and last n are marked as W1, W2, ..., Wn.
3. For two node Hu and Hv, connect it if there is a edge between u and v and can be visited in human form. Similar things goes for Wu and Wv.
4. Add a edge between every Hu and Wu.
5. Run DFS(Hsoruce) and see if you can reach Wdestination.

The best part is you don't create the above graph explicitly. You calculate the graph on the fly form the original one. And most graph algorithm actually uses another implicit graph which is calculated on the fly (yes, Dijkstra too).