These are my codes for the problem Compression Algorithm of ACM ICPC 2018 online round.
I don't understand what is the problem with the first solution.
Note: The expected precision was 10^-6.
Image 1
Image 2
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Codeforces (c) Copyright 2010-2026 Михаил Мирзаянов
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Auto comment: topic has been updated by rishi_07 (previous revision, new revision, compare).
Well they say "Your answer will be considered correct if the absolute error is less than 10 - 6". With
printf("%.6lf")there is possibility you will print something with error equal to 10 - 6 which is considered wrong.Hi, please check the first image. There I used setprecision(10). Still WA. This is not only my case, check this discussion on codechef Link
I can explain why the
setprecisioncode gives WA but I have no idea about theprintf. setprecision includes the number of digits before the decimal point also . So setting it to 9 + 6 should work.In this Link user swetankmodi claimed to have used setprecision(18) but still got WA.
This gave us AC
yes, but the solution posted by @bhishma uses long double but I used only double. Maybe that caused the issue?
You're wrong. From http://www.cplusplus.com/reference/iomanip/setprecision/
"Sets the decimal precision to be used to format floating-point values on output operations". Beside we submitted with setprecision(8) and it got accepted.
Actually my main language is Java so I might be wrong , but I have seen this issue in some old codeforces blog . In that case how can you explain this
There is a difference between cout<<fixed<<setprecision(10)<<x; and cout<<setprecision(10)<<x;
Example:
long double x=1000000000000.13232; cout<<fixed<<setprecision(10)<<x;
Output: 1000000000000.1323242188
long double x=1000000000000.13232; cout<<setprecision(10)<<x;
Output: 1e+12
If u dont use fixed and the number is reasonably large u might lose precision