How to solve problem B ?
This problem looks similar to SPOJ-WATER
Someone please explain the approach to this problem?
Thank you!
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3390 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 156 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
How to solve problem B ?
This problem looks similar to SPOJ-WATER
Someone please explain the approach to this problem?
Thank you!
Name |
---|
I approached it in a way similar to Bellman Ford Algorithm . Take a matrix W and fill all the entries with infinity except the ones present in the border of the grid ie. i = 0 || i = (R - 1) || j = 0 || j = (C - 1) where i, j are the row index and column index respectively.
Now for each cell in the interior of the matrix water can come from 4 adjacent cells . We need to find the minimum of the incoming water from these cells and make this the new W[i][j] only if its greater than H[i][j]
For each cell with index i, j: min = min(W[x][y]) x, y adjacent to i, j and W[i][j] = max(min, H[i][j])
You need to run this relaxation for R * C times
My Java Code:
Link