#include<bits/stdc++.h>
 
using namespace std;
 
int main() {
    int t;
    cin >> t;
    while(t--) {
        string n;
        cin >> n;
        if((n.back() - '0') % 2 == 0) {
            cout << "0\n";
            continue;
        }
        if((n[0] - '0') % 2 == 0) {
            cout << "1\n";
            continue;
        }
        int count_2 = count(n.begin(), n.end(), '2');
        int count_4 = count(n.begin(), n.end(), '4');
        int count_6 = count(n.begin(), n.end(), '6');
        int count_8 = count(n.begin(), n.end(), '8');
        if(count_2 > 0 || count_4 > 0 || count_6 > 0 || count_8 > 0) {
            cout << "2\n";
            continue;
        }
        cout << "-1\n";
    }
    return 0;
}

#include <bits/stdc++.h>
 
using namespace std;
using ll = long long;
 
void solve() {
    ll a, b;
    cin >> a >> b;
    cout << min(min(a, b), (a + b) / 4) << '\n';
}
 
int main() {
    int t;
    cin >> t;
    for (int i = 0; i < t; ++i) {
        solve();
    }
    return 0;
}

#include <bits/stdc++.h>
 
using namespace std;
 
#define forn(i, n) for (int i = 0; i < int(n); i++)
 
int main() {
    int t;
    cin >> t;
    forn(tt, t) {
        int n;
        cin >> n;
        vector<int> a(n);
        forn(i, n)
            cin >> a[i];
        if (a[0] != n && a[n - 1] != n)
            cout << -1 << endl;
        else {
            for (int i = n - 1; i >= 0; i--)
                cout << a[i] << " ";
            cout << endl;
        }
    }
}

#include <bits/stdc++.h>
 
using namespace std;
 
void solve(){
    int n;
    cin >> n;
    vector<int> b(n + 1), p(n + 1), dist(n + 1, -1);
 
    for(int i = 1; i <= n; i++)
        cin >> b[i];
    for(int i = 1; i <= n; i++)
        cin >> p[i];
 
    if (b[p[1]] != p[1]){
        cout << -1 << '\n';
        return;
    }
 
    dist[p[1]] = 0;
    for(int i = 2; i <= n; i++){
        if(dist[b[p[i]]] == -1){
            cout << -1 << '\n';
            return;
        }
        dist[p[i]] = dist[p[i - 1]] + 1;
    }
 
    for(int i = 1; i <= n; i++) {
        cout << dist[i] - dist[b[i]] << ' ';
    }
    cout << '\n';
}
 
int main() {
    int t;
    cin >> t;
    while(t-- > 0) {
        solve();
    }
}

//
// Created by Vlad on 16.11.2021.
//
 
#include <bits/stdc++.h>
 
#define int long long
#define mp make_pair
#define x first
#define y second
#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()
 
typedef long double ld;
typedef long long ll;
 
using namespace std;
 
mt19937 rnd(143);
 
const int inf = 1e10;
const int M = 998244353;
const ld pi = atan2(0, -1);
const ld eps = 1e-4;
 
void solve() {
    int n, k;
    cin >> n >> k;
    vector<int> color(n, -1);
    deque<int> q;
    for(int i = 0; i < k; ++i){
        int x;
        cin >> x;
        color[--x] = 0;
        q.push_back(x);
    }
    color[0] = 1;
    q.push_back(0);
    vector<vector<int>> g(n);
    for(int i = 0; i < n - 1; ++i){
        int u, v;
        cin >> u >> v;
        g[--u].push_back(--v);
        g[v].push_back(u);
    }
    while(!q.empty()){
        int v = q.front();
        q.pop_front();
        for(int u: g[v]){
            if(color[u] == -1){
                color[u] = color[v];
                q.push_back(u);
            }
        }
    }
    for(int v = 1; v < n; ++v){
        if(g[v].size() == 1 && color[v] == 1){
            cout << "YES";
            return;
        }
    }
    cout << "NO";
}
 
bool multi = true;
 
signed main() {
    int t = 1;
    if (multi) {
        cin >> t;
    }
    for (; t != 0; --t) {
        solve();
        cout << "\n";
    }
    return 0;
}

#include <bits/stdc++.h>
 
#define int long long
#define mp make_pair
#define x first
#define y second
#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()
 
/*#pragma GCC optimize("Ofast")
#pragma GCC optimize("no-stack-protector")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,popcnt,abm,mmx,tune=native")
#pragma GCC optimize("fast-math")
*/
typedef long double ld;
typedef long long ll;
 
using namespace std;
 
mt19937 rnd(143);
 
const int inf = 1e10;
const int M = 998244353;
const ld pi = atan2(0, -1);
const ld eps = 1e-4;
 
vector<vector<int>> sl;
vector<int> nearest;
 
int count(int v, int dist, int p = -1){
    bool children = true;
    int s = 0;
    for(int u: sl[v]){
        if(u == p) continue;
        int c = count(u, dist + 1, v);
        if(c < 0) children = false;
        nearest[v] = min(nearest[v], nearest[u] + 1);
        s += c;
    }
    if(nearest[v] <= dist) return 1;
    if(s == 0 || !children) return -1;
    return s;
}
 
void solve() {
    int n, k;
    cin >> n >> k;
    sl.assign(n, vector<int>(0));
    nearest.assign(n, n);
    for(int i = 0; i < k; ++i){
        int x;
        cin >> x;
        --x;
        nearest[x] = 0;
    }
    for(int i = 1; i  < n; ++i){
        int u, v;
        cin >> u >> v;
        --u, --v;
        sl[u].emplace_back(v);
        sl[v].emplace_back(u);
    }
    cout << count(0, 0);
}
 
bool multi = true;
 
signed main() {
    //freopen("in.txt", "r", stdin);
    //freopen("in.txt", "w", stdout);
    /*ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);*/
    int t = 1;
    if (multi) {
        cin >> t;
    }
    for (; t != 0; --t) {
        solve();
        cout << "\n";
    }
    return 0;
}

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

#define forn(i, n) for (int i = 0; i < int(n); i++)

vector<ll> t, a;
ll s, tl;

const ll MAX = 1'000'000'000'000'000LL;

void build(int v, int l, int r) {
	if (l == r)
		t[v] = a[l];
	else {
		int m = (l + r) / 2;
		build (v * 2, l, m);
		build (v * 2 + 1, m + 1, r);
		t[v] = min(t[v * 2], t[v * 2 + 1]);
	}
}

void update(int v, int l, int r) {
	if (l == r)
		t[v] = MAX;
	else {
		int m = (l + r) / 2;
		if (tl <= m)
			update(v * 2, l, m);
		else
			update(v * 2 + 1, m + 1, r);
		t[v] = min(t[v * 2], t[v * 2 + 1]);
	}
}

int lower_bound_s(int v, int l, int r) {
	if (r < tl || (l == r && s < -t[v])) {
		return -1;
	}
    if (l == r || -t[v] <= s) {
        return r;
    }
	int m = (l + r) / 2;

	if (m < tl) {
        return lower_bound_s(2 * v + 1, m + 1, r);
	}
	if (s < -t[2 * v]) {
        return lower_bound_s(2 * v, l, m);
	}
	int res = lower_bound_s(2 * v + 1, m + 1, r);
	return (res == -1) ? m : res;
}


int main() {
    int tests;
    cin >> tests;
    forn(tt, tests) {
        int n;
        cin >> n >> s;
        t = vector<ll>(4 * n);
        a = vector<ll>(n);
        forn(i, n) {
            cin >> a[i];
        }
        for (int i = 1; i < n; ++i) {
            a[i] += a[i - 1];
        }
        build(1, 0, n - 1);
        int first = -1, second = -2;
        for (tl = 0; tl < n; ++tl) {
            int v = lower_bound_s(1, 0, n - 1);
            if (v != -1 && v - tl > second - first) {
                first = tl + 1;
                second = v + 1;
            }
            s -= a[tl];
            if (tl != 0) s += a[tl - 1];
            update(1, 0, n - 1);
        }
        if (first == -1) {
            cout << -1;
        } else {
            cout << first << " " << second;
        }
        cout << endl;
    }
}

#include <bits/stdc++.h>
 
using namespace std;
 
#define forn(i, n) for (int i = 0; i < int(n); i++)
#define sz(v) (int)v.size()
 
const int N = 1e6 + 50;
string a[N];
 
int n,m;
int ans;
 
void solve(int sum0) {
    vector<int> v;
    for (int sum = sum0, ad = 0, pref = 0; sum < n + m; sum += 2, ad++) {
        vector<int> cur;
        int li = max(0, sum - m + 1), ri = min(n - 1, sum);
        if (li > ri) continue;
 
        for (int i = li; i <= ri; i++) {
            int j = sum - i;
 
            if (a[i][j] == '1')
                cur.emplace_back(i);
        }
 
        while (pref != sz(v) && v[pref] + ad > ri) {
            pref++;
        }
        for (int i = pref; i < sz(v); i++) {
            int new_val = v[i];
            while (!cur.empty() && cur.back() - ad >= v[i]) {
                new_val = max(new_val, cur.back() - ad);
                cur.pop_back();
            }
            v[i] = new_val;
        }
        if (!cur.empty()) {
            v.emplace_back(cur.back() - ad);
            ans++;
        }
    }
}
 
int main() {
    int t;
    cin >> t;
 
    forn(tt, t) {
        cin >> n >> m;
 
        forn(i, n) {
            string s; 
            cin >> a[i];
        }
 
        ans = 0;
        solve(0);
        solve(1);
        
        cout << ans << '\n';
    }
}