| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | jiangly | 3670 |
| 3 | Kevin114514 | 3657 |
| 4 | maroonrk | 3355 |
| 5 | Um_nik | 3353 |
| 6 | squareOf105 | 3346 |
| 7 | tourist | 3343 |
| 8 | strapple | 3324 |
| 9 | heuristica | 3322 |
| 10 | jiangbowen | 3291 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | AmShZ | 143 |
| 5 | Um_nik | 141 |
| 6 | Errichto | 139 |
| 7 | adamant | 137 |
| 8 | BledDest | 133 |
| 8 | maroonrk | 133 |
| 10 | qwexd | 130 |
|
0
if someone is struggling with understanding problem-B, the key observation is there should be a number which can be completely absorbed into rest of the numbers. i.e. there is an a[i] whose set bits are [x1, x2, x3] and aj has set bits [x1, x3] and a[k] (k!=j && k!=i) has set bits [x2, x4, x5] then seq-a would be all elements in array and seq-b would be all elements in array except a[i] since those set bits already exist via rest of the elements |
| Name |
|---|


