In this problem(1070L - Odd Federalization), I used gaussian elimination (O(n^3)) but I have used bitset because I think it will be faster. Finally, I got AC (44701036) but I still don't understand all details of bitset's complexity. Thanks for reading my blog
→ Обратите внимание
До соревнования
WorldQuant Round 1 (Codeforces Round 1128, Div. 1 + Div. 2)
2 дня
Зарегистрироваться »
WorldQuant Round 1 (Codeforces Round 1128, Div. 1 + Div. 2)
2 дня
Зарегистрироваться »
*есть доп. регистрация
→ Лидеры (рейтинг)
| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | jiangly | 3670 |
| 3 | Kevin114514 | 3657 |
| 4 | maroonrk | 3355 |
| 5 | Um_nik | 3353 |
| 6 | squareOf105 | 3346 |
| 7 | tourist | 3343 |
| 8 | strapple | 3324 |
| 9 | heuristica | 3322 |
| 10 | jiangbowen | 3291 |
| Страны | Города | Организации | Всё → |
→ Лидеры (вклад)
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | AmShZ | 143 |
| 5 | Um_nik | 141 |
| 6 | Errichto | 139 |
| 7 | adamant | 137 |
| 8 | BledDest | 134 |
| 9 | maroonrk | 133 |
| 10 | qwexd | 130 |
→ Найти пользователя
→ Прямой эфир
Codeforces (c) Copyright 2010-2026 Михаил Мирзаянов
Соревнования по программированию 2.0
Время на сервере: 15.10.2026 06:06:55 (i1).
Десктопная версия, переключиться на мобильную.
При поддержке
See http://www.cplusplus.com/reference/algorithm/swap/. If you swap anything but two arrays, it's constant. That means even bitset or vector.
Its O(1) always because it swaps iterators/doesn't actually copy the contents over.
So when you see (sz(a) < sz(b)) swap(a,b) for thing like merge small to large this swap is constant (or else it would not be nlogn overall)
If I want to swap iteraters of 2 things a and b, I always use a.swap(b). But I can't use that way with bitset so I think it's O(n^3) without reducing by complexity of bitset. Tks you :3 :3
It's n/64 because data is stored insidebitset itself (like in an array but unlike in a vector)
Auto comment: topic has been updated by JioFell (previous revision, new revision, compare).