conceptual doubt

Правка en1, от HaabyHings, 2017-03-01 20:03:19

let there be 3 integers x, y, z
their multiplication (x * y * z) is can be calculated either as (x * y) * z or x * (y * z) // associativity holds
now assume x / (y * z) = x * (1 / y) * (1 / z)
let Y and Z be the multiplicative modular inverse of (1 / y) and (1 / z) respectively
then result can be written as x * Y * Z
here (x * Y) * Z != x * (Y * Z) { WHY ? } // associativity does not holds

Теги modular arithmetic, inverse, associativity, maths

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en1 Английский HaabyHings 2017-03-01 20:03:19 863 Initial revision (published)