Calculating (C(k, k) + C(k+1, k) + C(k+2, k) + ... + C(m, k)) modulo 1234567890 (m >= k) in 1 second? - Codeforces

→ Pay attention

Before contest
Rayan Programming Contest 2024 - Selection (Codeforces Round, Div. 1 + Div. 2)
4 days
Register now »

*has extra registration

→ Top rated

#	User	Rating
1	tourist	3993
2	jiangly	3743
3	orzdevinwang	3707
4	Radewoosh	3627
5	jqdai0815	3620
6	Benq	3564
7	Kevin114514	3443
8	ksun48	3434
9	Rewinding	3397
10	Um_nik	3396

Countries | Cities | Organizations

→ Top contributors

#	User	Contrib.
1	cry	167
2	Um_nik	163
3	maomao90	162
3	atcoder_official	162
5	adamant	159
6	-is-this-fft-	158
7	awoo	155
8	TheScrasse	154
9	Dominater069	153
10	nor	152

View all →

→ Find user

→ Recent actions

Detailed →

Calculating (C(k, k) + C(k+1, k) + C(k+2, k) + ... + C(m, k)) modulo 1234567890 (m >= k) in 1 second?

Revision en1, by xuanquang1999, 2016-08-16 15:48:48

Is there a way to do this?

History

Revisions

	Rev.	Lang.	By	When	Δ	Comment
	en2		xuanquang1999	2016-08-16 15:52:00	55	Tiny change: 'to do this?' -> 'to do this if m, k <= 10^9?\n\nPS: C here mean combination number.'
	en1		xuanquang1999	2016-08-16 15:48:48	127	Initial revision (published)