500E : NEW YEAR DOMINO

Правка en6, от ds_95, 2015-11-17 15:06:28

Please help me debug my solution for this problem NEW YEAR DOMINO

My submission :14311924

My Idea :

--Treat each domino as an interval.

--Then find connected components based on intersection.

--Store range of each connected component i.e. minL,maxR.

--for each query a,b

--define cost(cc[a],cc[b]) as cost of going from one connected component to another.

--cost(cc[a],cc[b]) = minL[cc[b]]-maxR[cc[a]] (given b>a).

--However min cost = sum of costs (starting from cc[a]) to next one till cc[b] reached.

История

 
 
 
 
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en7 Английский ds_95 2015-11-17 15:06:53 0 (published)
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