| # | User | Rating |
|---|---|---|
| 1 | tourist | 4009 |
| 2 | jiangly | 3823 |
| 3 | Benq | 3738 |
| 4 | Radewoosh | 3633 |
| 5 | jqdai0815 | 3620 |
| 6 | orzdevinwang | 3529 |
| 7 | ecnerwala | 3446 |
| 8 | Um_nik | 3396 |
| 9 | ksun48 | 3390 |
| 10 | gamegame | 3386 |
| # | User | Contrib. |
|---|---|---|
| 1 | cry | 164 |
| 1 | maomao90 | 164 |
| 3 | Um_nik | 163 |
| 4 | atcoder_official | 160 |
| 4 | adamant | 160 |
| 6 | -is-this-fft- | 158 |
| 7 | awoo | 157 |
| 8 | TheScrasse | 154 |
| 8 | Dominater069 | 154 |
| 8 | nor | 154 |
maximum points covered by segments
There are N points and M segments, the ith point is located at p[i] and the ith segment's size is s[i]. What is the maximum number of points that can be covered by these segments?
My current solution is O(N * 2^M * logN). Is there any better solution?
| Rev. | Lang. | By | When | Δ | Comment | |
|---|---|---|---|---|---|---|
| en3 |
|
start_over | 2024-05-04 08:06:45 | 4 | Tiny change: ' O(N * 2^M). Is the' -> ' O(N * 2^M * M). Is the' | |
| en2 |
|
start_over | 2024-05-04 07:46:41 | 7 | Tiny change: ' O(N * 2^M * logN). Is ther' -> ' O(N * 2^M). Is ther' | |
| en1 |
|
start_over | 2024-05-04 07:22:40 | 294 | Initial revision (published) |
