Is this code below works on all platform with C++11 compiler?
I know that earlier we had to to use "%I64d" for Windows platform and "%lld" for linux like platforms.
long long = (long long)1e18;
printf("%lld\n", a);
# | User | Rating |
---|---|---|
1 | jiangly | 3976 |
2 | tourist | 3815 |
3 | jqdai0815 | 3682 |
4 | ksun48 | 3614 |
5 | orzdevinwang | 3526 |
6 | ecnerwala | 3514 |
7 | Benq | 3482 |
8 | hos.lyric | 3382 |
9 | gamegame | 3374 |
10 | heuristica | 3357 |
# | User | Contrib. |
---|---|---|
1 | cry | 169 |
2 | -is-this-fft- | 165 |
3 | Um_nik | 161 |
3 | atcoder_official | 161 |
5 | djm03178 | 157 |
6 | Dominater069 | 156 |
7 | adamant | 154 |
8 | luogu_official | 152 |
9 | awoo | 151 |
10 | TheScrasse | 147 |
Is this code below works on all platform with C++11 compiler?
I know that earlier we had to to use "%I64d" for Windows platform and "%lld" for linux like platforms.
long long = (long long)1e18;
printf("%lld\n", a);
Hello everybody, I have no idea to this problem, have you ?
Chess association decided to assign new phone numbers to all the members.
The new numbers should be produced with a knight's move on a phone keypad. 0 and 8 are not valid leading digits.
For instance, the number 340-49-27 matches the criteria.
7 8 9
4 5 6
1 2 3
0
Create a program that computes the number of different phone numbers with a length N.
1 ≤ N ≤ 56'789
It is standard problem with small N, which can be solved by dynamic programming.
I tried to solve it with Matrix Exponentiation (of size 10x10). But it also TL ( O(10 ^ 3 * logn * BigInt) ), because of the multiplying very big numbers.
Name |
---|