noogler's blog

C++11: printf

By noogler, 12 years ago, translation, In English

Is this code below works on all platform with C++11 compiler?

I know that earlier we had to to use "%I64d" for Windows platform and "%lld" for linux like platforms. 

long long = (long long)1e18;
printf("%lld\n", a);
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12 years ago, hide # |
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No it doesn't.
UPD: I suddenly realised I might've been wrong. I do have problems with --std=gnu++11 but, apparently, there's no such problem with --std=c++11.

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12 years ago, hide # |
 
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you may check it in the Standard but as far as I remember it's now in standard so it should work in every compliant compiler.

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    12 years ago, hide # ^ |
     
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    Not that this means much when mingw is notoriously non-compliant. Ever tried printing long doubles? (Also, for some reason, you have to read doubles with %lf and print with %f, even though they should be equivalent).

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Strangely, it works on every compiler on Codeforces

P.S. WIN32 is defined, as I see

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12 years ago, hide # |
 
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It works. Even -std=c++11 -Wpedantic gives no warnings. It seems that the code is correct in ISO C++ 2011 Standard.

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