include

using namespace std;

void printstudent(student *Student);

typedef struct { char name[50];

}student;

int main() { student student1; strcpy(student1.name,"Douglas Brown"); printstudent(&student 1); } void printstudent(student *Student) { cout<name<<endl; }

master nichol, grandmaster egor, bmerry

KOFIOWUSU847
13 лет назад
4

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accidentallygivenfuck

13 лет назад, скрыть # |

For better view :

#include <iostream> // let me
#include <cstring>  // guess :)
using namespace std;

typedef struct {
	char name[50];
} student;

void printstudent(student &Student);

int main() {
	student student1;
	strcpy(student1.name, "Douglas Brown");
	printstudent(student1);
}

void printstudent(student &Student) {
	cout << Student.name << endl;
}

So what are you asking ?? :S

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KOFIOWUSU847

13 лет назад, скрыть # ^ |

i want to use this operator -> instead of . dot and wants pointer *Student instead.

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accidentallygivenfuck

13 лет назад, скрыть # ^ |

As far as I understand you, you are having compilation error.

You mistyped &student 1. It should be &student1.
You need to declare struct student before printstudent prototype.

Here is the correct one:

#include <iostream>
#include <cstring>
using namespace std;

typedef struct {
	char name[50];
} student;

void printstudent(student *Student);

int main() {
	student student1;
	strcpy(student1.name, "Douglas Brown");
	printstudent(&student1);
}

void printstudent(student *Student) {
	cout << Student->name << endl;
}

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