Can anyone explain the solution.. solution are posted on homepage, but it seems difficult to understand.
| # | User | Rating |
|---|---|---|
| 1 | jiangly | 3810 |
| 2 | Benq | 3676 |
| 3 | Kevin114514 | 3655 |
| 4 | maroonrk | 3463 |
| 5 | strapple | 3390 |
| 6 | Um_nik | 3387 |
| 7 | tourist | 3384 |
| 8 | heuristica | 3322 |
| 9 | turmax | 3319 |
| 10 | jiangbowen | 3291 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 155 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | Um_nik | 143 |
| 5 | AmShZ | 141 |
| 6 | Errichto | 139 |
| 7 | adamant | 137 |
| 8 | maroonrk | 134 |
| 9 | BledDest | 132 |
| 10 | qwexd | 129 |
Can anyone explain the solution.. solution are posted on homepage, but it seems difficult to understand.
| Name |
|---|



Let
. Then the answer to the problem is
(except for the case b = 1 where the sum is infinite). So we want to compute Fa(x).
We see that
. Hence, Fa + 1(x) = xF'a(x).
We have
. Then
, and so on. It's easy to see that
, where Pa is a polynomial of degree a. Substituting this expression into recurrent equation for Fa we get
Pa + 1(x) = xP'a(x)(1 - x) + (a + 1)xPa(x).
So we can compute the polynomial Pa using this recurrent equation.