I see people using "ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);" I personally use "ios::sync_with_stdio(0); cin.tie(0);" without the "cout.tie(0);". What is the difference? Is the first option faster than the second?
Codeforces Round 1133 (Div. 1, Div. 2) is coming soon! Register here.
→ Pay attention
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | Kevin114514 | 3659 |
| 3 | jiangly | 3640 |
| 4 | turmax | 3450 |
| 5 | tourist | 3382 |
| 6 | strapple | 3360 |
| 7 | Um_nik | 3354 |
| 8 | squareOf105 | 3348 |
| 9 | maroonrk | 3312 |
| 10 | idontwannadothis…e | 3191 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 155 |
| 2 | nik_exists | 151 |
| 3 | maspy | 149 |
| 4 | AmShZ | 145 |
| 5 | Um_nik | 143 |
| 6 | Errichto | 139 |
| 7 | BledDest | 136 |
| 8 | adamant | 134 |
| 9 | maroonrk | 132 |
| 10 | cry | 130 |
→ Find user
→ Recent actions
Codeforces (c) Copyright 2010-2026 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Nov/07/2026 02:36:54 (g2).
Desktop version, switch to mobile version.
Supported by
coutis not tied to anything by default. So,cout.tie(false)is useless.Then why do people still use it?
Because they saw it from another person who also doesn't know that it's useless, and they keep using it without noticing because it does nothing — not even any trouble.
Oh, I get it, they are just using it because other mindless blokes are using it too.