Here is the link to the editorial. Feel free to discuss problems and ask me questions. I'll be glad to improve the editorial with your comments.
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1 | tourist | 4009 |
2 | jiangly | 3821 |
3 | Benq | 3736 |
4 | Radewoosh | 3631 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3388 |
10 | gamegame | 3386 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
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1 | cry | 164 |
1 | maomao90 | 164 |
3 | Um_nik | 163 |
4 | atcoder_official | 161 |
5 | -is-this-fft- | 158 |
6 | awoo | 157 |
7 | adamant | 156 |
8 | TheScrasse | 154 |
8 | nor | 154 |
10 | Dominater069 | 153 |
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I'm not getting div2 c ...how it is linked to knapsack?? can you explain the logic more clearly??
We want to find the probability of gaining i scores in games other than G. It's similar to finding in how many ways we gain i scores. It's a knapsack problem.
we need to gain i scores in such a way that after adding G to it .It must become greater than n*(n+1)/4.In other words we need to look for only those i's such that after adding G to it ,it can become greater than n*(n+1)/4.Am i right?
and we'll use knapsack to find those i's and we won't be using G as a weight?
Correct.
Thank you :)