Hi. I have following problem. Yesterday I tried to solve this problem The same code with emplace_back does not pass the system test. However the same code with push_back passes the system test. So my question is: What is happening here ? Link to the submission with push_back Link to the submission with emplace_back
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push_back creates a copy of the object you want to insert before pushing it to the vector and hence it modifies the type accordingly (in this case to long double) whereas emplace_back just moves the argument to the vector and hence the element remain of the same type and here you can check that atan2 is a built-in function that returns a double and not a long double.
So your problem was with precision and not with the use of push_back and emplace_back.
Thank you! Now i got it. When I cast it to long double it gets accepted.
That doesn't make sense to me,
emplace_backjust calls some constructor with the arguments, and there thedoublewould be cast tolong doublein my understanding.Unless you need to worry about things like exception handling, don't use
emplace_back. It isn't faster.emplace_back can also be used to append objects with fewer characters. For example for a vector<pair<int,int>> you can do: vec.emplace_back(a,b)
Similarly, you can go with vec.push_back({a, b}).
But
vec.emplace_back(a, b)has one more character thanvec.push_back({a, b})... :DOk, you got me there. Just to pretend Im not completely wrong, you can also use emplace_back when you use structs or classes. For example for a struct for points named pt and for vector vec you can use vec.emplace_back(x,y) in comparision to vec.push_back(pt(x,y)). (Plus you can do #define eb emplace_back)