Hi guys! I've come across a problem which asks for the number of divisors of C(n) = n * ( 2 ^ n ) + 1, with n <= 60. Can anyone find a fast solution for it?
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3390 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | cry | 164 |
1 | maomao90 | 164 |
3 | Um_nik | 163 |
4 | atcoder_official | 160 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 157 |
8 | TheScrasse | 154 |
8 | Dominater069 | 154 |
8 | nor | 154 |
Hi guys! I've come across a problem which asks for the number of divisors of C(n) = n * ( 2 ^ n ) + 1, with n <= 60. Can anyone find a fast solution for it?
Name |
---|
You can find count of divisors in which is enough for that problem.
Thank you very much