Is 10^9 computation is possible before 2.00 seconds? If not possible,how my solution works of following problem? Problem link: http://codeforces.me/problemset/problem/851/C Submission: http://codeforces.me/contest/851/submission/30089349
| # | User | Rating |
|---|---|---|
| 1 | jiangly | 3810 |
| 2 | Benq | 3676 |
| 3 | Kevin114514 | 3655 |
| 4 | maroonrk | 3463 |
| 5 | strapple | 3447 |
| 6 | Um_nik | 3387 |
| 7 | heuristica | 3322 |
| 8 | turmax | 3317 |
| 9 | tourist | 3307 |
| 10 | jiangbowen | 3291 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 156 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | Um_nik | 141 |
| 5 | Errichto | 139 |
| 6 | adamant | 137 |
| 7 | AmShZ | 135 |
| 8 | BledDest | 132 |
| 9 | maroonrk | 131 |
| 10 | qwexd | 129 |
Is 10^9 computation is possible before 2.00 seconds? If not possible,how my solution works of following problem? Problem link: http://codeforces.me/problemset/problem/851/C Submission: http://codeforces.me/contest/851/submission/30089349
| Name |
|---|



It depends on what you mean by "computation". I assume here you mean that your solution is O(n3) and n ≤ 103 hence the number 109, but for each triplet of points you process here, you are making many more auxiliary "computations", each of which take different amounts of time. If I understand you correctly, generally brute forcing 109 cases will not pass in 2 seconds, but I think your continue; and return; statements in your function pruned the search considerably (it can be shown that, by at latest the 12th iteration, there will be an acute angle).