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SPOJ problem stuck!!!
By red_coder, 13 years ago, In English

Can anyone pls help me to solve this problem .... HAYBALE

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13 years ago, # |
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anyone please help...

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13 years ago, # |
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We have a new array q[N], for each FJ instructions l..r doing q[l]++, q[r + 1]--. After all instructions for integer cnt = 0 from 1..N we will increase cnt += q[i] and h[i] = cnt, then sort(h, h + N) and print h[(N + 1) / 2].

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    13 years ago, # ^ |
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    dude i am not able to understand the logic behind your solution...

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13 years ago, # |
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Another solution is to use segment tree and make an update on [A..B] segment for each instruction.

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13 years ago, # |
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It's a usaco problem.Although the code is very small the solution behind this code is not very simple. http://usaco.org/current/data/sol_restack.html

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    13 years ago, # ^ |
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    dude can u pls post the link of the Question...

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13 years ago, # |
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1) calculate resulting heights of each stack 2) sort them 3) output middle element

step 1 can be done using segment trees, RSQ — Range Sum Query, QSRT decomposition, etc.
the simplest way to count resulting heights:
to remember each query L, R in addition array dh[L]++, dh[R + 1]--; then curH = 0; for(i = 0; i < n; i++) {curH += dh[i]; h[i] = curH;} sort(h, h + n); cout << h[((n) +-1) / 2 +-1] << endl;`

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