Can somebody please explain how to use the Möbius function to solve this problem. https://www.hackerrank.com/contests/w3/challenges/gcd-product
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3856 |
2 | jiangly | 3747 |
3 | orzdevinwang | 3706 |
4 | jqdai0815 | 3682 |
5 | ksun48 | 3591 |
6 | gamegame | 3477 |
7 | Benq | 3468 |
8 | Radewoosh | 3462 |
9 | ecnerwala | 3451 |
10 | heuristica | 3431 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 168 |
2 | -is-this-fft- | 162 |
3 | Dominater069 | 160 |
4 | Um_nik | 159 |
5 | atcoder_official | 156 |
6 | adamant | 153 |
6 | djm03178 | 153 |
8 | luogu_official | 149 |
9 | awoo | 147 |
10 | TheScrasse | 146 |
Can somebody please explain how to use the Möbius function to solve this problem. https://www.hackerrank.com/contests/w3/challenges/gcd-product
Название |
---|
Let f(n,m) denote the number of pairs (x, y), such that x ≤ n, y ≤ m, and gcd(x,y) = 1. WLOG, assume n ≥ m
Using inclusion exclusion,
If we store an array of prefix sums of mobius function, then f(n, m) can be calculated in
.
Now let G(g, n, m) be the number of pairs (x, y), such that x ≤ n, y ≤ m, and gcd(x, y) = g.
Clearly,
. There are clearly
different values of this for all the g's
Our required answer is
. Considering the different ranges in which G(g, n, m) is same, this can be calculated in O(n).
Thanks for the nice explanation.
I solved it little differently. After the step
Now I define a function f, such that for any prime p, f(pa) = p else f(n) = 1. It must be noted that
, Now If I substitute this expression in above expression and rearrange the multiplication we get
which reduces to
. Now this is very simple to evaluate.