I was solving TCO 2015 and saw this code, someone knows it for?
public static int getMask(int n){
return n != 0 ? 1 << n % 10 | getMask(n / 10) : 0;
}
I was solving TCO 2015 and saw this code, someone knows it for?
public static int getMask(int n){
return n != 0 ? 1 << n % 10 | getMask(n / 10) : 0;
}
| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | jiangly | 3670 |
| 3 | Kevin114514 | 3657 |
| 4 | maroonrk | 3355 |
| 5 | Um_nik | 3353 |
| 6 | squareOf105 | 3346 |
| 7 | tourist | 3343 |
| 8 | strapple | 3324 |
| 9 | heuristica | 3322 |
| 10 | jiangbowen | 3291 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | AmShZ | 143 |
| 5 | Um_nik | 141 |
| 6 | Errichto | 139 |
| 7 | adamant | 137 |
| 8 | BledDest | 134 |
| 9 | maroonrk | 133 |
| 10 | qwexd | 130 |
| Название |
|---|



the method build a set where the k-th bit is 1 if the the digit k appears in N, 0 <= k <= 9.
Example, N = 42594 getMask(N) = 1000110100 in binary, notice that the rightmost bit represents the status of the digit 0.