if a1+a2+a3+a4>b1+b2+b3+b4 then
is it right to say that p.a1+q.a2+r.a3+s.a4>p.b1+q.b2+r.b3+s.b4?????
if a1+a2+a3+a4>b1+b2+b3+b4 then
is it right to say that p.a1+q.a2+r.a3+s.a4>p.b1+q.b2+r.b3+s.b4?????
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No, even if $$$p, q, r, s \ge 0$$$ you can't say for sure, counter-example: $$$a_1 = 5, a_2 = 5, a_3 = 3, a_4 = 5$$$ & $$$b_1 = 4, b_2 = 4, b_3 = 5, b_4 = 4$$$ then with $$$p = 1, q = 1, r = 2, s = 1$$$ the inequality does not hold.
will it work for a situation like p>q>r>s????
No, just permute sequence a and sequence b according to the coefficient sequence and you will get a counter-case.