This year there will be a single preliminary round for all the three sites. The contest will be on Codedrills from 11AM IST on 26th November.
Let's use this blog to discuss the round after it ends.
Best of luck to everyone participating tomorrow.
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This year there will be a single preliminary round for all the three sites. The contest will be on Codedrills from 11AM IST on 26th November.
Let's use this blog to discuss the round after it ends.
Best of luck to everyone participating tomorrow.
Название |
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Today during the mock round, some teams got marks in partial. Does anyone have a idea about that.
Also does anybody have the issue where college name is incorrectly showing the "&" as "&".
what's the approach for problem E today ( ICPC mock ) ? Treelection
You can find Treelection editorial here.
Thankyou sir!!
The contest will start in less than 30 minutes now. All the best.
Can someone explain the casework for Three Person Tree Game please.
can you explain the logic used to solve this and also the code if you can? I tried finding the intersection node between a, b, and c and did something with the distance between them.
You were on the right path, you just have to find several cases based on distance inequality. Each of them could lead to different winner.
I used the same approach too. There were just $$$4$$$ cases: Sort the distances (non decreasing order), now WLOG, let the smallest distance be $$$A$$$ to the intersection node, the 2nd smallest be $$$B$$$ to the intersection, and the 3rd be $$$C$$$ to the intersection.
1) All distances are equal ---> DRAW
2) The two smallest distances are equal ---> $$$B$$$ wins
3) The two biggest distances are equal ---> $$$A$$$ wins
4) All distances are distinct ---> $$$A$$$ wins
It seems like I missed a case though, which lead to a WA :c
thought of the same solution but i was too late for fixing some bugs.
THANKS!
So did you try it again? What case did you miss , i was thinking on similar lines
What is the number of slots for each site can anyone tell? For Amritapuri it's 250 but for rest no idea.
Where does it say 250 slots for Amritapuri?
link
Thanks!
Is there any college cap? We got rank 277 and College rank 1. Can we qualify for Amritapuri?
Yes, you will qualify for Amrita easily. Congrats!
Hopefully yes because out of top 250 many are from the same colleges mostly IITs, NITs, and BIT so you should qualify
Chennai regional has approx 100 slots. As mentioned https://icpc-iiitdm.vercel.app/preliminary-rules.pdf
kanpur 100 ig
Is it available in codeforces (gym) ?
What's the qualifaction criteria for amritapuri? My team placed 6th overall but 2nd in college (😓). Do we qualify?
If overthinking had a face...
congrats for single digit rank! OP!
In the scoreboard there seems to be some teams which have registered for three regionals. Will they be disqualified because in the rules it was mentioned that we have to select only two regionals?
Such teams have gotten the mail to back out from one region. So finally, they will be considered only for any two regionals.
Giving them choice is unfair because then everyone would have registered for three regionals and would have chosen the best two.
The teams were asked to select the regions before the start of the contest.
My team is 739th Air , College rank 1 . Any chance of Amritapuri regionals ?
Very Less
Probably The Only day of me being unhappy because of being in IIT, rank-159, college rank -7.
Bro we got Rank 70 and College Rank 6 :)
Sad
I just checked,There are only 194 unique colleges out of top 700 teams.So,those who are getting rank less than 800 will qualify for amritapuri for sure...
Did you check manually or write a script or something?
I tried web scrapping but codedrills not supported that so did manually using map xD. Took me almost an hour. And this information is accurate so relax. Btw what was your rank?
Bro u should have prepared that hard !!! you would have been top 50
Sometimes , Amritapuri changes their selection criteria by not selecting the top team from every college and instead prioritising rank .
bro after this new criteria released by amritapuri ,is there any chance of 795 rank(CR-1) qualifying?
No bro,teams with rank less than 710 will qualify for amritapuri.Sorry for your loss.
Hii :), How you calculated that?, our team has 775 rank.
Manually..
I copied rank list in excel read it using a script and like that our rank came out to be around 240. that's why I was asking.
After that, the top team from each institute who solved at least one problem is invited until available slots are filled. If the top team is already selected from an institute, it is skipped.
How you interpreted this point. if teams is already selected ,institute is skipped?
Yes,your list is Amrita puri special,mine is for overall.So, chances are there.
739 ?
75% chances are there,because my list for overall not for amritapuri specific.Wish you Luck
Let's say IIT Bombay got selected twice below AIR 135 which solved 3 problems. Are they going to be selected again with AIR of 136 if they solved 2 problems ?
Thats confusing, I think they won't select that 3rd team
Bro instead of thinking these scenarios just git gud
okay and ?
and try next year
looks like somebody has no hope for this year
and who might that person be?
Does anyone know, how many seats are there for kanpur region, and I got (AIR 279) and (College Rank 1, for kanpur region), so what are my chances of qualifying for regionals? Also, usually how many days does it take for the results to be declared?
Probably this should help. link
Thanks for the link.
This is the list for the previous year, if I am not wrong.
There are 150 teams in the list and this year there are approx 100 teams. Beacuse on site it was written 2023 above so I thought it was of 2023.
Yes
Bro you were too close,before you there are 106 unique colleges and seats for kanpur is 100 only. Sorry for your loss but you will qualify for amritapuri if you have filled the form.
Are you sure? One of my friends checked for the same, and he informed me that there are 86 unique colleges only above us in kanpur region.
I didn't checked for a specific region. It's overall,you can expect some increase in your rank .
Yeah I guess, in kanpur we might be 87th
Congrats bro you qualified, see you soon in regionals :)
Thanks bro, and Congratulations to you too!! Looking forward to meeting you :)
Does anyone know when the results will be out and how many slots are there for kanpur this time? Last time i checked there were approx.150 slots including both kanpur and mathura but this time only kanpur is hosting.
It is 100 approx slots, as per the selection criteria doc.
Link: https://kanpur.indiaicpc.in/Prelim_rules.pdf
Results are out for kanpur region
The selection criteria for Chennai or Kanpur mention that :
Select top 10 (ten) ranked teams for Onsite Contest
Remove these 10 teams from the Rank List
Select the top-ranked team from each distinct school or institute
So top 10 participants from the mixed rank list or the top 10 from the rank list specific to a region will be removed?
specific to region
Congratulations to everyone who qualified. What is your opinion on difficulty rating of problem A in terms of codeforces difficulty ratings ? (the Virat Kohli century one)
Max 1700
Wow so it was not that hard.I remember there were under 100 submissions on it and all onsites have atleast 100 seats. Is it safe to say almost everyone who solved that problem would have qualified ? (Ignoring the college ranking based disqualification)
Anyone else waiting for Chennai preliminary results ?? Please update me with the link if you got it....!!
What are selection criteria for amritapuri?
https://amritaicpc.in/?page_id=157
When will the qualified teams for Chennai Region be announced??
Results are out now !! Which team are you in ??
Congratulations to everyone who made it! Hopefully see you in the next year ¯_(ツ)_/¯
Does anybody know when results of amritapuri region will come ?
Diversity hiring is garbage, whether it's for job roles or anything else.
all results are out
Amritapuri : https://amritaicpc.in/?page_id=157
Its not opening!
It's working on my side, or just go to thier website.