if we know log(a) and log(b) how we can find log(a+b) approximately to real value?
if we know log(a) and log(b) how we can find log(a+b) approximately to real value?
| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | Kevin114514 | 3659 |
| 3 | jiangly | 3640 |
| 4 | turmax | 3450 |
| 5 | tourist | 3408 |
| 6 | strapple | 3360 |
| 7 | Um_nik | 3354 |
| 8 | squareOf105 | 3348 |
| 9 | maroonrk | 3312 |
| 10 | idontwannadothis…e | 3191 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Qingyu | 155 |
| 2 | nik_exists | 151 |
| 3 | maspy | 149 |
| 4 | AmShZ | 145 |
| 5 | Um_nik | 143 |
| 6 | Errichto | 139 |
| 7 | BledDest | 136 |
| 8 | adamant | 135 |
| 9 | maroonrk | 132 |
| 10 | cry | 130 |
log(exp(log(a))+exp(log(b)))
If a and b are close numbers, you can approximate using the following formula:
For example, if a = b, then
why
and 
need to be close for this formula to work? 
(in addition to 
, ofcourse) sufficient?
isn't
This formula works OK, but if
is some small number, you can remember its logarithm and thus approximate 
without calculator or paper — that was the point.
ah i see what u mean. thanks! :)