Hey! Does anybody know how to solve this? Given n segments, count how many pairs of segments have a common point. There are no 2 overlapping segments and the segments are can make any angle with the origin of the cartesian plane.
# | User | Rating |
---|---|---|
1 | jiangly | 3898 |
2 | tourist | 3840 |
3 | orzdevinwang | 3706 |
4 | ksun48 | 3691 |
5 | jqdai0815 | 3682 |
6 | ecnerwala | 3525 |
7 | gamegame | 3477 |
8 | Benq | 3468 |
9 | Ormlis | 3381 |
10 | maroonrk | 3379 |
# | User | Contrib. |
---|---|---|
1 | cry | 168 |
2 | -is-this-fft- | 165 |
3 | Dominater069 | 160 |
3 | Um_nik | 160 |
5 | atcoder_official | 159 |
6 | djm03178 | 157 |
7 | adamant | 153 |
8 | luogu_official | 150 |
9 | awoo | 149 |
10 | TheScrasse | 146 |
How to count the intersections of n segments in n log n
Hey! Does anybody know how to solve this? Given n segments, count how many pairs of segments have a common point. There are no 2 overlapping segments and the segments are can make any angle with the origin of the cartesian plane.
Name |
---|