Here's the problem from last year's ACM ICPC Dhaka Regional Preliminary Round.
It says to calculate sod(n) [sum of digits of n] while n >= 10. Here n = a^b, (0<= a,b <= 10^50,000 and a+b>0 ) Any thoughts on how to solve this?
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3390 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 156 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
Repeated Digit Sum of A^B
Here's the problem from last year's ACM ICPC Dhaka Regional Preliminary Round.
It says to calculate sod(n) [sum of digits of n] while n >= 10. Here n = a^b, (0<= a,b <= 10^50,000 and a+b>0 ) Any thoughts on how to solve this?
Rev. | Lang. | By | When | Δ | Comment | |
---|---|---|---|---|---|---|
en2 | simplecomplex | 2018-06-06 14:09:23 | 6 | Tiny change: 's of n]** until **n >= 10' -> 's of n]** while **n >= 10' | ||
en1 | simplecomplex | 2018-06-06 14:07:06 | 340 | Initial revision (published) |
Name |
---|