A. Very Simple Problem
Problem Summary: Check if an integer $$$n$$$ has an odd divisor greater than one.
Key Insight: A number has no odd divisor $$$ \gt 1$$$ if and only if it is a power of two.
Reasoning:
- Even $$$\times$$$ Even = Even
- Even $$$\times$$$ Odd = Even
- Odd $$$\times$$$ Even = Even
- Odd $$$\times$$$ Odd = Odd
So, only odd numbers can generate odd divisors, and powers of two are formed entirely by 2's.
Implementation Tip: To check if $$$n$$$ is a power of 2:
(n & (n - 1)) == 0
Time Complexity: $$$\mathcal{O}(1)$$$ per test case.
B. Simple Problem
Problem Summary: Given array $$$a$$$, split it into $$$k \gt 1$$$ subsegments and maximize the GCD of the sums of each segment.
Key Insight: It suffices to only try $$$k = 2$$$, because:
So combining segments doesn't reduce the GCD.
Algorithm:
- Compute total sum $$$s = \sum a_i$$$.
- For every prefix sum $$$p_i$$$, compute $$$\gcd(p_i, s - p_i)$$$.
- Track the maximum.
Time Complexity: $$$\mathcal{O}(n)$$$ per test case.
C. Descent Problem
Problem Summary: Given $$$n$$$, $$$m$$$, and $$$k$$$, find number of valid values of $$$a_{n+1}$$$ such that the array formed by applying $$$a_i = a_{i+1} \bmod i$$$ has exactly $$$k$$$ distinct values.
Case Analysis:
- $$$k = 1$$$: Always 1 valid way ($$$a_{n+1} = 0$$$).
- $$$k = 2$$$:
If $$$m \leq n$$$: $$$m$$$ ways.
- Else: $$$n + \left\lfloor \frac{m - n}{n} \right\rfloor$$$.
- $$$k = 3$$$:
If $$$m \leq n$$$: 0 ways.
- Else: $$$m - n - \left\lfloor \frac{m - n}{n} \right\rfloor$$$.
- $$$k \gt 3$$$: 0 ways.
Time Complexity: $$$\mathcal{O}(1)$$$ per test case.
D. Hard Problem
Problem Summary: Can all elements of an array be made equal using $$$a_i = a_i + (a_i \bmod 10)$$$?
Key Observations:
- Numbers divisible by 10 remain fixed.
- Remainder 5 can only be applied once.
- Others follow a cyclic behavior mod 20.
Strategy:
- If any number is divisible by 5:
- Apply operation once to all.
- Check if they are equal.
- Else:
- Normalize all values modulo 20 by applying the operation.
- Check if all values converge.
Time Complexity: $$$\mathcal{O}(n)$$$ per test case.
E. Very Hard Problem
Problem Summary: Given arrays $$$a$$$ and $$$b$$$, compute:
Use GCD identity:
Let $$$d = \gcd(a_2 - a_1, \dots, a_n - a_1)$$$. Then,
Steps:
- Compute $$$d$$$ once.
- For each $$$b_j$$$, compute $$$\gcd(a_1 + b_j, d)$$$.
Time Complexity: $$$\mathcal{O}(n + m)$$$
F. The Legendary One!!
Problem Summary: Given arrays $$$a$$$ and $$$b$$$, find integer $$$k$$$ such that $$$b_i = a_i \bmod k$$$ (after shuffling).
From:
Let $$$\Delta = \sum a_i - \sum b_i$$$
Cases:
- If $$$\Delta = 0$$$: Any $$$k \gt \max a_i$$$ works.
- Else: Try all divisors of $$$\Delta$$$.
Algorithm:
- For each divisor $$$d$$$, compute $$$a_i \bmod d$$$.
- Check if multiset matches $$$b$$$.
Time Complexity: $$$\mathcal{O}(n \sqrt{\Delta})$$$
That concludes the editorial. If you have any doubts or suggestions, feel free to comment below.



