Codeforces Round 975 (Div. 1) |
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Finished |
You have some cards. An integer between $$$1$$$ and $$$n$$$ is written on each card: specifically, for each $$$i$$$ from $$$1$$$ to $$$n$$$, you have $$$a_i$$$ cards which have the number $$$i$$$ written on them.
There is also a shop which contains unlimited cards of each type. You have $$$k$$$ coins, so you can buy at most $$$k$$$ new cards in total, and the cards you buy can contain any integer between $$$\mathbf{1}$$$ and $$$\mathbf{n}$$$, inclusive.
After buying the new cards, you must partition all your cards into decks, according to the following rules:
Find the maximum possible size of a deck after buying cards and partitioning them optimally.
Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.
The first line of each test case contains two integers $$$n$$$, $$$k$$$ ($$$1 \leq n \leq 2 \cdot 10^5$$$, $$$0 \leq k \leq 10^{16}$$$) — the number of distinct types of cards and the number of coins.
The second line of each test case contains $$$n$$$ integers $$$a_1, a_2, \ldots, a_n$$$ ($$$0 \leq a_i \leq 10^{10}$$$, $$$\sum a_i \geq 1$$$) — the number of cards of type $$$i$$$ you have at the beginning, for each $$$1 \leq i \leq n$$$.
It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$2 \cdot 10^5$$$.
For each test case, output a single integer: the maximum possible size of a deck if you operate optimally.
93 13 2 25 42 6 1 2 42 1001410065408 1000000000010 87 4 6 6 9 3 10 2 8 72 122 22 700 11 013 02 1 23 10 3 3
2 3 1 7 2 2 1 1 2
In the first test case, you can buy one card with the number $$$1$$$, and your cards become $$$[1, 1, 1, 1, 2, 2, 3, 3]$$$. You can partition them into the decks $$$[1, 2], [1, 2], [1, 3], [1, 3]$$$: they all have size $$$2$$$, and they all contain distinct values. You can show that you cannot get a partition with decks of size greater than $$$2$$$, so the answer is $$$2$$$.
In the second test case, you can buy two cards with the number $$$1$$$ and one card with the number $$$3$$$, and your cards become $$$[1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 4, 4, 5, 5, 5, 5]$$$, which can be partitioned into $$$[1, 2, 3], [1, 2, 4], [1, 2, 5], [1, 2, 5], [2, 3, 5], [2, 4, 5]$$$. You can show that you cannot get a partition with decks of size greater than $$$3$$$, so the answer is $$$3$$$.
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