Codeforces Round 892 (Div. 2) |
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Finished |
Andrey is just starting to come up with problems, and it's difficult for him. That's why he came up with a strange problem about permutations$$$^{\dagger}$$$ and asks you to solve it. Can you do it?
Let's call the cost of a permutation $$$p$$$ of length $$$n$$$ the value of the expression:
Find the maximum cost among all permutations of length $$$n$$$.
$$$^{\dagger}$$$A permutation of length $$$n$$$ is an array consisting of $$$n$$$ distinct integers from $$$1$$$ to $$$n$$$ in arbitrary order. For example, $$$[2,3,1,5,4]$$$ is a permutation, but $$$[1,2,2]$$$ is not a permutation ($$$2$$$ appears twice in the array), and $$$[1,3,4]$$$ is also not a permutation ($$$n=3$$$ but there is $$$4$$$ in the array).
Each test consists of multiple test cases. The first line contains a single integer $$$t$$$ ($$$1 \le t \le 30$$$) — the number of test cases. The description of the test cases follows.
The only line of each test case contains a single integer $$$n$$$ ($$$2 \le n \le 250$$$) — the length of the permutation.
It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$500$$$.
For each test case, output a single integer — the maximum cost among all permutations of length $$$n$$$.
52431020
2 17 7 303 2529
In the first test case, the permutation with the maximum cost is $$$[2, 1]$$$. The cost is equal to $$$2 \cdot 1 + 1 \cdot 2 - \max (2 \cdot 1, 1 \cdot 2)= 2 + 2 - 2 = 2$$$.
In the second test case, the permutation with the maximum cost is $$$[1, 2, 4, 3]$$$. The cost is equal to $$$1 \cdot 1 + 2 \cdot 2 + 4 \cdot 3 + 3 \cdot 4 - 4 \cdot 3 = 17$$$.
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