the difficulty of this problem could change depending on whether the array is a permutation or not. A permutation is a more friendly one

That's true. Thanks :).

Oh yeah 😂 I forgot it's python 🥲.

Shorter solution for problem B

for _ in range(int(input())):
  w, h, a, b = map(int, input().split())
  x1, y1, x2, y2 = map(int, input().split())
  if (
    ((t:=abs(x1-x2))%a == 0 and t > 0) or
    ((t:=abs(y1-y2))%b == 0 and t > 0)
  ):
    print('YES')
  else: print('NO')

You can avoid that by using string keys or tuple keys. those work better than integer keys.