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| # | User | Contrib. |
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-19
same |
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+9
Canon round. |
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0
Man. Problem B turned out to be so easy, but I wasted all my time debugging solution for C. |
|
0
Or something like this :) Pattern example |
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0
Could you tell how please? |
|
+10
I think that this round had very interesting problems with pretty beautiful possible solutions. Thanks for the contest! |
|
0
The contest isn't over yet. |
|
+1
Same lol |
|
0
Dude, you are breaking the rules of the contest. |
|
-6
Agreed. |
|
0
How to solve the "Letter Exchange"? |
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0
Thanks! Didn't notice that it was already out. |
|
0
What are the ideas behind D and F? |
|
0
Ah, okay. Sorry. |
|
0
It's not. |
|
-7
Or ko_osaga ._. |
|
0
Let's gooo!! |
|
0
To be honest, there is not that much logic behind that. Was wondering, what would happen, and desided to try this dumb idea out... |
|
+1
Wow. People hate this comment so much :/ |
|
0
Seems like checking if ( x & 1 || x & x >> 1 ) is false works too. |
|
0
C is a harder version of https://codeforces.me/problemset/problem/1512/A |
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+8
Congrats |
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0
Didn't notice lol |
|
-7
Noticed that in examples a and b are equal to x +- some number. Found such numbers using bruteforce for x in [1, 256] and found out that there is either no solution or at least one solution with x+-x/2. |
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0
Good job!) |
|
-11
No. You just need to check if x is even and if (x + x/2) ^ (x/2) is equal to x. If both conditions are true, print x+x/2 and x/2 else -1. |
|
+6
Finally I was able to use first 31 digits of pi from my template :D |
|
+3
Please no NP-hard problems. Please no NP-hard problems. :D |
|
+1
Bye bye my hopes and chances to become pupil... |
|
0
First time in a while I was able to pass pretests on C and now the round is unrated :( |
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0
Friendships here are in fact subscriptions. If you want to subscribe to someone, press the grey star near their nickname in their profile. |
|
+1
Hate permutations, hate sortings, hate myself. Goodbye chance to become pupil :( |
|
0
OMG. Cyan round. |
|
+16
What did I say wrong? |
|
0
Well, I figured out how to use this website and now I am cyan... kind of... :D |
|
+3
. |
|
+6
Thanks for fast editorial. |
|
0
A was very easy, B is easy too if you know how to use Wolfram Alpha or are just good at finding patterns, but TL's at C and D suck. |
|
0
Good luck! |
|
0
Congrats! |
|
0
Alts/bots for bonus hacks. |
|
0
Could anybody explain to me why and how char in my A problem solution(185801559) turn into integer? |
|
+23
|
|
0
The feeling when you screw up C for more than half an hour because you forgot how c++ grid coords work... again. And then I got late for 2-3 damn seconds. Hate myself... |
|
0
Very interesting round. Can't wait for the editorial to see the D problem solution with diffrent numbers. |
|
0
Dunno about the idea of the authors but I've came to a pretty beautiful solution with repeating any number if n is odd. (num ^ num ^ ... ^ num = num) and (num*n/n = num). And if number is even, you can just print 1, 3 and 2 (n — 2) times. |
|
+1
Or long long |
|
0
1 2 1 9 0 and 2 are valleys so the answer is "no", but your code says "yes". |
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+22
Pinely Round 1 (Div.0 + Div.1) |
|
0
Yay. There is an editorial |
|
0
I'm wondering if there will be an editorial for this. |
|
0
Didn't solve even A :) Have the same feelings after this competition. |
|
0
Just every single time I think that I can't get results worse than previous time, I somehow manage to do this anyway. At least the next competition is div 4 round... |
|
+1
The feeling when Div. 3 round was more problematic for you than Div. 2 round XD |
|
+4
What if it is my 5th rated round? Will I become trusted participant if I will solve a problem in it? |
|
0
Current rating: 880, solved problems: 8. My goals are to finally figure out how to compete on this website and to achieve cyan :) |
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