Can someone suggest a website where I can host a private contest for particular users for free.
Or some PC application that will do the same job (besides e-judge).
Thanks in advance.
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | Kevin114514 | 3659 |
| 3 | jiangly | 3640 |
| 4 | turmax | 3450 |
| 5 | tourist | 3382 |
| 6 | strapple | 3360 |
| 7 | Um_nik | 3354 |
| 8 | squareOf105 | 3348 |
| 9 | maroonrk | 3312 |
| 10 | idontwannadothis…e | 3191 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 156 |
| 2 | nik_exists | 151 |
| 3 | maspy | 149 |
| 4 | AmShZ | 145 |
| 5 | Um_nik | 143 |
| 6 | Errichto | 139 |
| 7 | BledDest | 136 |
| 8 | adamant | 135 |
| 9 | maroonrk | 132 |
| 10 | cry | 130 |
Can someone suggest a website where I can host a private contest for particular users for free.
Or some PC application that will do the same job (besides e-judge).
Thanks in advance.
This is just to remind that tomorrow on November 8 the ACM-ICPC Subregional contest will be held in Georgia, Armenia, Kazakhstan, Uzbekistan, Russia (St. Petersburg, Novosibirsk, Vladivostok). Good luck to all teams...!!!
I am trying to solve the problem 320B - Ping-Pong (Easy Version) with BFS, but getting wrong answer. The idea is as follows: If we add a pair (a,b) to our set, then I check the ways with remaining pairs in my massive "mark". So if we can move from pair x to y than mark[x][y]=1. Otherwise it equals 0.
In case of checking way form x to y I am using BFS. I starting to seek from peak x until y will be found. Otherwise I print No.
Please someone help me to find the mistake in my 3956387 solution.
Thanks.
| Name |
|---|


