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Name |
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"x" is the length of days for 1 chandeliers for diff. color
"y" is the length of days for 2 chandeliers for diff. color
ANS is max ( x , y )
Here we do a binary search on lengths "x" and "y" to find positions of differences.
number of "pos" should be equal to "k" ,i.e. days to make Vasya angry
same if the case for ## pos ≡ y ( mod m ) .. >> [0 <= pos < m ]
NOW SOLVE THE EQUATIONS TO FIND X and Y , and print max ( X , Y )
Thank you. I have got some idea.