Does anyone know how to solve this problem?
http://www.spoj.com/problems/LQDNUMS/
Or at least please give me the references for it. Thanks a lot in advance.
Does anyone know how to solve this problem?
http://www.spoj.com/problems/LQDNUMS/
Or at least please give me the references for it. Thanks a lot in advance.
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | Kevin114514 | 3659 |
| 3 | jiangly | 3640 |
| 4 | turmax | 3450 |
| 5 | tourist | 3382 |
| 6 | strapple | 3360 |
| 7 | Um_nik | 3354 |
| 8 | squareOf105 | 3348 |
| 9 | maroonrk | 3312 |
| 10 | idontwannadothis…e | 3191 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 155 |
| 2 | nik_exists | 151 |
| 3 | maspy | 149 |
| 4 | AmShZ | 145 |
| 5 | Um_nik | 143 |
| 6 | Errichto | 139 |
| 7 | BledDest | 136 |
| 8 | adamant | 134 |
| 9 | maroonrk | 132 |
| 10 | cry | 130 |
| Name |
|---|



I have some ideas to solve it in polynomial time, but it's too slow.
Let F(N) be the length of the result string. We have to find N, such that F(N) == M.
Use binary search to find N. F(N) can be calculated using DP and fast matrix exponentiation. I know how to do it with about 18-36 matrices of size K x K, K ~ 18 * 10 * 2.
No, i was wrong with matrix exponentiation. I think there is kind of dp, we have to divide iterval [1..N] into several ones with the same prefix. for example for N = 1234 ther will be
[1..999] for all numbers with length < length(N)
[1000..1199] — 1 234
[1200..1229] — 12 34
[1230..1234] — 123 4
for each of these intervals we have to use this dp recursively.