https://codeforces.me/contest/1237/submission/62742100
Looks N^3, but seems to be N^2 after constructing many cases. Any proofs/can you hack it?
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You can try this input:
Something like this makes your algorithm work in $$$O(n^3)$$$ time. You need $$$O(n)$$$ points on each diagonal:
In contest I submitted the same idea but I was sorting first.
my submission
I tried (CUSTOM INVOCATION) it passed your testcase in 31ms, I also believe that it remains O(N^3). How it pass all testcases and your testcase ? mnbvmar