Here line 12 and 14 should output the same value (expected output 1)
But why when I call range(i,mn,mx) it outputs 0?
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Supported by
you should write
instead of
why ?
If you write
#define range(i,mn,mx) ((i >= mn) && (i <= mx)?1:0)thenrange(x||y,0,1)will be like((x||y >= mn) && (x||y <= mx)?1:0)=>((x||(y >= mn)) && (x||(y <= mx))?1:0)