Here is the statement of problem B from the most recent contest (#571) for those who missed it. 571 — B
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What was the test case 3? I did (a+1) (b+1) /6.
If I'm not mistaken it likely was
4 4or something like that.Your code would correctly produce
4for that.However the expected answer according to the problem author's code would have been
3which is clearly wrong as the following arrangement exists :Hi sir Can you please explain how you achieved that formula? Thank you.
In every 2x3 you can put one . so how many 2x3 blocks we have in our grid?
Thank you for the reply sir. perhaps I am not understanding correctly, but maximum you can put in a 2x3 is actually 2, and when you have an perfect number of 2x3s your can actually fit more (example is 4x6).
http://codeforces.me/blog/entry/68048 Read Comment