Hello everyone. It would be great if someone gives a solution for this problem https://www.codechef.com/problems/CZ17R2Q2. Thank you.
# | User | Rating |
---|---|---|
1 | tourist | 3993 |
2 | jiangly | 3743 |
3 | orzdevinwang | 3707 |
4 | Radewoosh | 3627 |
5 | jqdai0815 | 3620 |
6 | Benq | 3564 |
7 | Kevin114514 | 3443 |
8 | ksun48 | 3434 |
9 | Rewinding | 3397 |
10 | Um_nik | 3396 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 155 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
10 | djm03178 | 152 |
Hello everyone. It would be great if someone gives a solution for this problem https://www.codechef.com/problems/CZ17R2Q2. Thank you.
Name |
---|
Maintain a
stack
of lengthn
. For everyi-th
element, if it is positive, push it into the stack. If it is negative, let's call itx
. Check ifstack.top() == -x
. If yes, popstack.top()
and increase the counter by 2.Solution complexity — O(n).
I think for the input : 1 2 3 -1. Your solution will give 0 as the answer whereas the ans should be 2. Correct me if i am wrong.
How do you get answer 2 for 1 2 3 -1 ?
The question asks for the longest balanced subsequence. So if we take 1 -1 as the subsequence from 1 2 3 -1, we end up with a balanced subsequence of length 2.
I guess you have to pick consecutive positions because for sample testcase 1 -1 2 3 -2 answer is 2 (1 and -1). The answer could be 4 (1, -1, 2, -2) if it would be allowed to pick any positions. So for input 1 2 3 -1 answer is 0.
Basically, you have to find the largest subarray whose sum is equal to zero. You can look at my submission here