214A - Система уравнений Of course, we can do this using brute-force method. Does a better way exists please share it. Thanks.
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214A - Система уравнений Of course, we can do this using brute-force method. Does a better way exists please share it. Thanks.
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$$$a + b ^ 2 = n$$$, so $$$a = n - b ^ 2$$$, so $$$a ^ 2 + b = (n - b ^ 2) ^ 2 + b = b ^ 4 - 2 * n * b ^ 2 + n ^ 2 + b = m$$$.
The last equation can be solved in $$$O(1)$$$. If you don't like math, don't open this link
you won't have much fun, if you try to solve that for $$$b$$$...
I'm sure every heathy person won't solve this problem using Ferrari's formula
Iterate over $$$a$$$ up to $$$\sqrt n$$$. For each $$$a$$$, compute $$$b$$$ from the first equation and check if the second equation holds. The complexity is $$$O(\sqrt n)$$$. If you want something better, have fun with ugly equations.