| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | Kevin114514 | 3659 |
| 3 | jiangly | 3640 |
| 4 | turmax | 3450 |
| 5 | tourist | 3408 |
| 6 | strapple | 3360 |
| 7 | Um_nik | 3354 |
| 8 | squareOf105 | 3348 |
| 9 | maroonrk | 3312 |
| 10 | idontwannadothis…e | 3191 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 154 |
| 2 | nik_exists | 151 |
| 3 | maspy | 149 |
| 4 | AmShZ | 146 |
| 5 | Um_nik | 143 |
| 6 | Errichto | 139 |
| 7 | BledDest | 136 |
| 8 | adamant | 135 |
| 9 | maroonrk | 133 |
| 10 | cry | 130 |
| Name |
|---|



Nobody??? Not even an opinion.....
It's proved, years don't pass along your mind :) After 3 years, you take a look at the problem again, think of it about 15 minutes, and you get a new optimization that solves it :) In this case that the longest meaningful code must be less than the length of the message :) solution
First of all, thank you kindly for source code with solution! However, I am a bit confused with 1 particular moment: why in the solution it is ok to pick n starting from m/2? How is that possible that it provides correct result if half of possible keys are ignored? Thanks in advance!
If a key of length k is valid, then that key squared (of length 2 * k) is valid too, so we only need to check key lengths that can't be squared, aka starting from m / 2.