I don't understand why in some dp problems dp[0] is equal to 0,like the coin change problem.Can someone explain this to me?
→ Pay attention
→ Streams
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | jiangly | 3670 |
| 3 | Kevin114514 | 3657 |
| 4 | maroonrk | 3355 |
| 5 | Um_nik | 3353 |
| 6 | squareOf105 | 3346 |
| 7 | tourist | 3343 |
| 8 | strapple | 3324 |
| 9 | heuristica | 3322 |
| 10 | jiangbowen | 3291 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | AmShZ | 143 |
| 5 | Um_nik | 141 |
| 6 | Errichto | 139 |
| 7 | adamant | 137 |
| 8 | BledDest | 133 |
| 8 | maroonrk | 133 |
| 10 | qwexd | 130 |
→ Find user
→ Recent actions
Codeforces (c) Copyright 2010-2026 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Oct/14/2026 02:06:20 (n2).
Desktop version, switch to mobile version.
Supported by
It depends on what your table actually represents.
Why is not picking anything is also counted as a way?
the empty subset almost always counts as satisfying the condition to most problems.
afaik, in the coin change problem dp[0] = 1, so what do you mean?