In this submisson: 2431151 In that line: "if(hour[i]==hour[i-1]&&min[i]==min[i-1]){"
In the beginning, i=0 so that hour[i-1] means hour[-1].Can someone please explain how can this pass the pretests?
# | User | Rating |
---|---|---|
1 | tourist | 3993 |
2 | jiangly | 3743 |
3 | orzdevinwang | 3707 |
4 | Radewoosh | 3627 |
5 | jqdai0815 | 3620 |
6 | Benq | 3564 |
7 | Kevin114514 | 3443 |
8 | ksun48 | 3434 |
9 | Rewinding | 3397 |
10 | Um_nik | 3396 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 155 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
10 | nor | 152 |
In this submisson: 2431151 In that line: "if(hour[i]==hour[i-1]&&min[i]==min[i-1]){"
In the beginning, i=0 so that hour[i-1] means hour[-1].Can someone please explain how can this pass the pretests?
Name |
---|
what can i do?
You can be POLITE.Thats all...
Well I try run this code
on Costum Test in codeforces. It return 0 and did not give runtime error. I don't know what they use when compiling, but maybe this can explain why that code pass the pretest
UPDT I mean it produce output 0 and did not give runtime error
In C++, a[i] means *(a+i). This code accesses the memory cell located 4 bytes before than hour[0].
Thanks for your help