Can we apply extend Extended Euclidean algorithm for negative numbers?
Like for 3*x-4*y=1 output will be x=3 , y=2 .
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Why don't you just try it out?
Btw, even if it doesn't work, you can solve 3*x + 4*y = 1, receive the answer (x, y) to this modified problem, and the answer to your original problem will be (x, -y).
ok got it!, Thanks.